For solving this problem,
use can be made of the time needed by the cork to reach the floor,
t = 1.4 s, which we know is
1.2 m below the launching point of the cork. This quantity correspond to
the cork displacement of
y = 1.2 mhe initial velocity of the cork can be calculated
using the formula
g is the
acceleration of gravity. Thus, solving for the initial velocity,
v_{0y},
in the previous relation,
.
And the initial velocity becomes
.

Knowing the initial velocity
of the cork, the maximum height can be calculated from the formula,
,
(F_F 5), since
at
the velocity of the cork is zero,
.
The maximum height can be calculated,
.
Substituting the numerical values
. 